A private addressing scheme used in OUM network is class C which is 192.198.0.0/16 and the default subnet mask is 255.255.255.0
The numbers faculties was 10 , which mean 10 subnets is needed,
Then :
2 4 = 16 subnets ( > 10)
Then, it will be 4 bits borrowed from the host to
create additional networks.
To find the number of usable hosts where 4 bits remaining can be calculated by using formula:
24 - 2 = usable hosts
16 – 2 = 14 usable host
So, the network address with its prefix length will
be: 192.198.0.0/28.
The new Subnet mask will be : 255.255.255.240
To get the magic number we can look at the table below
:
From the table we can conclude the magic number is 16
Two IPv4 addresses are used in each subnet to
represent the network address and the broadcast address.
From the table above, we can conclude that :
The network address assigned to IT Center is at 6th available subnet which the IP Address is :
192.198.0.80
From this network address (192.198.0.80 ) , we can assign the 4th available address is:
The 4th available address for OUM Learning System Server is 192.198.0.84
for more detail can check our youtube video :
https://www.youtube.com/watch?v=EJI6NTTP63k
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